# Chapter 8 - Applying Machine Learning To Sentiment Analysis¶

Note that the optional watermark extension is a small IPython notebook plugin that I developed to make the code reproducible. You can just skip the following line(s).

In [1]:
%load_ext watermark
%watermark -a 'Sebastian Raschka' -u -d -v -p numpy,pandas,matplotlib,sklearn,nltk

Sebastian Raschka
last updated: 2016-09-29

CPython 3.5.2
IPython 5.1.0

numpy 1.11.1
pandas 0.18.1
matplotlib 1.5.1
sklearn 0.18
nltk 3.2.1


The use of watermark is optional. You can install this IPython extension via "pip install watermark". For more information, please see: https://github.com/rasbt/watermark.

### Overview¶

In [28]:
# Added version check for recent scikit-learn 0.18 checks
from distutils.version import LooseVersion as Version
from sklearn import __version__ as sklearn_version


# Obtaining the IMDb movie review dataset¶

A) If you are working with Linux or MacOS X, open a new terminal windowm cd into the download directory and execute

tar -zxf aclImdb_v1.tar.gz

### Compatibility Note:¶

I received an email from a reader who was having troubles with reading the movie review texts due to encoding issues. Typically, Python's default encoding is set to 'utf-8', which shouldn't cause troubles when running this IPython notebook. You can simply check the encoding on your machine by firing up a new Python interpreter from the command line terminal and execute

>>> import sys
>>> sys.getdefaultencoding()



If the returned result is not 'utf-8', you probably need to change your Python's encoding to 'utf-8', for example by typing export PYTHONIOENCODING=utf8 in your terminal shell prior to running this IPython notebook. (Note that this is a temporary change, and it needs to be executed in the same shell that you'll use to launch ipython notebook.

Alternatively, you can replace the lines

with open(os.path.join(path, file), 'r') as infile:
...
...
df.to_csv('./movie_data.csv', index=False)



by

with open(os.path.join(path, file), 'r', encoding='utf-8') as infile:
...
...
df.to_csv('./movie_data.csv', index=False, encoding='utf-8')



in the following cells to achieve the desired effect.

In [2]:
import pyprind
import pandas as pd
import os

# change the basepath to the directory of the
# unzipped movie dataset

#basepath = '/Users/Sebastian/Desktop/aclImdb/'
basepath = './aclImdb'

labels = {'pos': 1, 'neg': 0}
pbar = pyprind.ProgBar(50000)
df = pd.DataFrame()
for s in ('test', 'train'):
for l in ('pos', 'neg'):
path = os.path.join(basepath, s, l)
for file in os.listdir(path):
with open(os.path.join(path, file), 'r', encoding='utf-8') as infile:
df = df.append([[txt, labels[l]]], ignore_index=True)
pbar.update()
df.columns = ['review', 'sentiment']

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Shuffling the DataFrame:

In [3]:
import numpy as np

np.random.seed(0)
df = df.reindex(np.random.permutation(df.index))


Optional: Saving the assembled data as CSV file:

In [4]:
df.to_csv('./movie_data.csv', index=False)

In [5]:
import pandas as pd


Out[5]:
review sentiment
0 In 1974, the teenager Martha Moxley (Maggie Gr... 1
1 OK... so... I really like Kris Kristofferson a... 0
2 ***SPOILER*** Do not read this, if you think a... 0

### Note¶

If you have problems with creating the movie_data.csv file in the previous chapter, you can find a download a zip archive at https://github.com/rasbt/python-machine-learning-book/tree/master/code/datasets/movie

# Introducing the bag-of-words model¶

...

## Transforming documents into feature vectors¶

By calling the fit_transform method on CountVectorizer, we just constructed the vocabulary of the bag-of-words model and transformed the following three sentences into sparse feature vectors:

1. The sun is shining
2. The weather is sweet
3. The sun is shining, the weather is sweet, and one and one is two
In [6]:
import numpy as np
from sklearn.feature_extraction.text import CountVectorizer

count = CountVectorizer()
docs = np.array([
'The sun is shining',
'The weather is sweet',
'The sun is shining, the weather is sweet, and one and one is two'])
bag = count.fit_transform(docs)


Now let us print the contents of the vocabulary to get a better understanding of the underlying concepts:

In [7]:
print(count.vocabulary_)

{'one': 2, 'sweet': 5, 'the': 6, 'shining': 3, 'weather': 8, 'and': 0, 'two': 7, 'is': 1, 'sun': 4}


As we can see from executing the preceding command, the vocabulary is stored in a Python dictionary, which maps the unique words that are mapped to integer indices. Next let us print the feature vectors that we just created:

Each index position in the feature vectors shown here corresponds to the integer values that are stored as dictionary items in the CountVectorizer vocabulary. For example, the rst feature at index position 0 resembles the count of the word and, which only occurs in the last document, and the word is at index position 1 (the 2nd feature in the document vectors) occurs in all three sentences. Those values in the feature vectors are also called the raw term frequencies: tf (t,d)—the number of times a term t occurs in a document d.

In [8]:
print(bag.toarray())

[[0 1 0 1 1 0 1 0 0]
[0 1 0 0 0 1 1 0 1]
[2 3 2 1 1 1 2 1 1]]


## Assessing word relevancy via term frequency-inverse document frequency¶

In [9]:
np.set_printoptions(precision=2)


When we are analyzing text data, we often encounter words that occur across multiple documents from both classes. Those frequently occurring words typically don't contain useful or discriminatory information. In this subsection, we will learn about a useful technique called term frequency-inverse document frequency (tf-idf) that can be used to downweight those frequently occurring words in the feature vectors. The tf-idf can be de ned as the product of the term frequency and the inverse document frequency:

$$\text{tf-idf}(t,d)=\text{tf (t,d)}\times \text{idf}(t,d)$$

Here the tf(t, d) is the term frequency that we introduced in the previous section, and the inverse document frequency idf(t, d) can be calculated as:

$$\text{idf}(t,d) = \text{log}\frac{n_d}{1+\text{df}(d, t)},$$

where $n_d$ is the total number of documents, and df(d, t) is the number of documents d that contain the term t. Note that adding the constant 1 to the denominator is optional and serves the purpose of assigning a non-zero value to terms that occur in all training samples; the log is used to ensure that low document frequencies are not given too much weight.

Scikit-learn implements yet another transformer, the TfidfTransformer, that takes the raw term frequencies from CountVectorizer as input and transforms them into tf-idfs:

In [12]:
from sklearn.feature_extraction.text import TfidfTransformer

tfidf = TfidfTransformer(use_idf=True, norm='l2', smooth_idf=True)
print(tfidf.fit_transform(count.fit_transform(docs)).toarray())

[[ 0.    0.43  0.    0.56  0.56  0.    0.43  0.    0.  ]
[ 0.    0.43  0.    0.    0.    0.56  0.43  0.    0.56]
[ 0.5   0.45  0.5   0.19  0.19  0.19  0.3   0.25  0.19]]


As we saw in the previous subsection, the word is had the largest term frequency in the 3rd document, being the most frequently occurring word. However, after transforming the same feature vector into tf-idfs, we see that the word is is now associated with a relatively small tf-idf (0.45) in document 3 since it is also contained in documents 1 and 2 and thus is unlikely to contain any useful, discriminatory information.

However, if we'd manually calculated the tf-idfs of the individual terms in our feature vectors, we'd have noticed that the TfidfTransformer calculates the tf-idfs slightly differently compared to the standard textbook equations that we de ned earlier. The equations for the idf and tf-idf that were implemented in scikit-learn are:

$$\text{idf} (t,d) = log\frac{1 + n_d}{1 + \text{df}(d, t)}$$

The tf-idf equation that was implemented in scikit-learn is as follows:

$$\text{tf-idf}(t,d) = \text{tf}(t,d) \times (\text{idf}(t,d)+1)$$

While it is also more typical to normalize the raw term frequencies before calculating the tf-idfs, the TfidfTransformer normalizes the tf-idfs directly.

By default (norm='l2'), scikit-learn's TfidfTransformer applies the L2-normalization, which returns a vector of length 1 by dividing an un-normalized feature vector v by its L2-norm:

$$v_{\text{norm}} = \frac{v}{||v||_2} = \frac{v}{\sqrt{v_{1}^{2} + v_{2}^{2} + \dots + v_{n}^{2}}} = \frac{v}{\big (\sum_{i=1}^{n} v_{i}^{2}\big)^\frac{1}{2}}$$

To make sure that we understand how TfidfTransformer works, let us walk through an example and calculate the tf-idf of the word is in the 3rd document.

The word is has a term frequency of 3 (tf = 3) in document 3, and the document frequency of this term is 3 since the term is occurs in all three documents (df = 3). Thus, we can calculate the idf as follows:

$$\text{idf}("is", d3) = log \frac{1+3}{1+3} = 0$$

Now in order to calculate the tf-idf, we simply need to add 1 to the inverse document frequency and multiply it by the term frequency:

$$\text{tf-idf}("is",d3)= 3 \times (0+1) = 3$$
In [13]:
tf_is = 3
n_docs = 3
idf_is = np.log((n_docs+1) / (3+1))
tfidf_is = tf_is * (idf_is + 1)
print('tf-idf of term "is" = %.2f' % tfidf_is)

tf-idf of term "is" = 3.00


If we repeated these calculations for all terms in the 3rd document, we'd obtain the following tf-idf vectors: [3.39, 3.0, 3.39, 1.29, 1.29, 1.29, 2.0 , 1.69, 1.29]. However, we notice that the values in this feature vector are different from the values that we obtained from the TfidfTransformer that we used previously. The nal step that we are missing in this tf-idf calculation is the L2-normalization, which can be applied as follows:

$$\text{tfi-df}_{norm} = \frac{[3.39, 3.0, 3.39, 1.29, 1.29, 1.29, 2.0 , 1.69, 1.29]}{\sqrt{[3.39^2, 3.0^2, 3.39^2, 1.29^2, 1.29^2, 1.29^2, 2.0^2 , 1.69^2, 1.29^2]}}$$$$=[0.5, 0.45, 0.5, 0.19, 0.19, 0.19, 0.3, 0.25, 0.19]$$$$\Rightarrow \text{tfi-df}_{norm}("is", d3) = 0.45$$

As we can see, the results match the results returned by scikit-learn's TfidfTransformer (below). Since we now understand how tf-idfs are calculated, let us proceed to the next sections and apply those concepts to the movie review dataset.

In [14]:
tfidf = TfidfTransformer(use_idf=True, norm=None, smooth_idf=True)
raw_tfidf = tfidf.fit_transform(count.fit_transform(docs)).toarray()[-1]
raw_tfidf

Out[14]:
array([ 3.39,  3.  ,  3.39,  1.29,  1.29,  1.29,  2.  ,  1.69,  1.29])
In [15]:
l2_tfidf = raw_tfidf / np.sqrt(np.sum(raw_tfidf**2))
l2_tfidf

Out[15]:
array([ 0.5 ,  0.45,  0.5 ,  0.19,  0.19,  0.19,  0.3 ,  0.25,  0.19])

## Cleaning text data¶

In [16]:
df.loc[0, 'review'][-50:]

Out[16]:
'is seven.<br /><br />Title (Brazil): Not Available'
In [17]:
import re
def preprocessor(text):
text = re.sub('<[^>]*>', '', text)
emoticons = re.findall('(?::|;|=)(?:-)?(?:\)|$|D|P)', text) text = re.sub('[\W]+', ' ', text.lower()) +\ ' '.join(emoticons).replace('-', '') return text  In [18]: preprocessor(df.loc[0, 'review'][-50:])  Out[18]: 'is seven title brazil not available' In [19]: preprocessor("</a>This :) is :( a test :-)!")  Out[19]: 'this is a test :) :( :)' In [20]: df['review'] = df['review'].apply(preprocessor)  ## Processing documents into tokens¶ In [21]: from nltk.stem.porter import PorterStemmer porter = PorterStemmer() def tokenizer(text): return text.split() def tokenizer_porter(text): return [porter.stem(word) for word in text.split()]  In [22]: tokenizer('runners like running and thus they run')  Out[22]: ['runners', 'like', 'running', 'and', 'thus', 'they', 'run'] In [23]: tokenizer_porter('runners like running and thus they run')  Out[23]: ['runner', 'like', 'run', 'and', 'thu', 'they', 'run'] In [24]: import nltk nltk.download('stopwords')  [nltk_data] Downloading package stopwords to [nltk_data] /Users/Sebastian/nltk_data... [nltk_data] Package stopwords is already up-to-date!  Out[24]: True In [25]: from nltk.corpus import stopwords stop = stopwords.words('english') [w for w in tokenizer_porter('a runner likes running and runs a lot')[-10:] if w not in stop]  Out[25]: ['runner', 'like', 'run', 'run', 'lot'] # Training a logistic regression model for document classification¶ Strip HTML and punctuation to speed up the GridSearch later: In [26]: X_train = df.loc[:25000, 'review'].values y_train = df.loc[:25000, 'sentiment'].values X_test = df.loc[25000:, 'review'].values y_test = df.loc[25000:, 'sentiment'].values  In [29]: from sklearn.pipeline import Pipeline from sklearn.linear_model import LogisticRegression from sklearn.feature_extraction.text import TfidfVectorizer if Version(sklearn_version) < '0.18': from sklearn.grid_search import GridSearchCV else: from sklearn.model_selection import GridSearchCV tfidf = TfidfVectorizer(strip_accents=None, lowercase=False, preprocessor=None) param_grid = [{'vect__ngram_range': [(1, 1)], 'vect__stop_words': [stop, None], 'vect__tokenizer': [tokenizer, tokenizer_porter], 'clf__penalty': ['l1', 'l2'], 'clf__C': [1.0, 10.0, 100.0]}, {'vect__ngram_range': [(1, 1)], 'vect__stop_words': [stop, None], 'vect__tokenizer': [tokenizer, tokenizer_porter], 'vect__use_idf':[False], 'vect__norm':[None], 'clf__penalty': ['l1', 'l2'], 'clf__C': [1.0, 10.0, 100.0]}, ] lr_tfidf = Pipeline([('vect', tfidf), ('clf', LogisticRegression(random_state=0))]) gs_lr_tfidf = GridSearchCV(lr_tfidf, param_grid, scoring='accuracy', cv=5, verbose=1, n_jobs=-1)  Note: Some readers encountered problems running the following code on Windows. Unfortunately, problems with multiprocessing on Windows are not uncommon. So, if the following code cell should result in issues on your machine, try setting n_jobs=1 (instead of n_jobs=-1 in the previous code cell). In [30]: gs_lr_tfidf.fit(X_train, y_train)  Fitting 5 folds for each of 48 candidates, totalling 240 fits  [Parallel(n_jobs=-1)]: Done 42 tasks | elapsed: 43.9min [Parallel(n_jobs=-1)]: Done 192 tasks | elapsed: 228.2min [Parallel(n_jobs=-1)]: Done 240 out of 240 | elapsed: 265.3min finished  Out[30]: GridSearchCV(cv=5, error_score='raise', estimator=Pipeline(steps=[('vect', TfidfVectorizer(analyzer='word', binary=False, decode_error='strict', dtype=<class 'numpy.int64'>, encoding='utf-8', input='content', lowercase=False, max_df=1.0, max_features=None, min_df=1, ngram_range=(1, 1), norm='l2', preprocessor=None, smooth_idf=True, ...nalty='l2', random_state=0, solver='liblinear', tol=0.0001, verbose=0, warm_start=False))]), fit_params={}, iid=True, n_jobs=-1, param_grid=[{'vect__tokenizer': [<function tokenizer at 0x11851c6a8>, <function tokenizer_porter at 0x11851c730>], 'vect__ngram_range': [(1, 1)], 'vect__stop_words': [['i', 'me', 'my', 'myself', 'we', 'our', 'ours', 'ourselves', 'you', 'your', 'yours', 'yourself', 'yourselves', 'he', 'him', 'his', '...alty': ['l1', 'l2'], 'vect__norm': [None], 'vect__ngram_range': [(1, 1)], 'vect__use_idf': [False]}], pre_dispatch='2*n_jobs', refit=True, return_train_score=True, scoring='accuracy', verbose=1) In [31]: print('Best parameter set: %s ' % gs_lr_tfidf.best_params_) print('CV Accuracy: %.3f' % gs_lr_tfidf.best_score_)  Best parameter set: {'vect__tokenizer': <function tokenizer at 0x11851c6a8>, 'clf__C': 10.0, 'vect__stop_words': None, 'clf__penalty': 'l2', 'vect__ngram_range': (1, 1)} CV Accuracy: 0.897  In [32]: clf = gs_lr_tfidf.best_estimator_ print('Test Accuracy: %.3f' % clf.score(X_test, y_test))  Test Accuracy: 0.899  #### Start comment:¶ Please note that gs_lr_tfidf.best_score_ is the average k-fold cross-validation score. I.e., if we have a GridSearchCV object with 5-fold cross-validation (like the one above), the best_score_ attribute returns the average score over the 5-folds of the best model. To illustrate this with an example: In [36]: from sklearn.linear_model import LogisticRegression import numpy as np if Version(sklearn_version) < '0.18': from sklearn.cross_validation import StratifiedKFold from sklearn.cross_validation import cross_val_score else: from sklearn.model_selection import StratifiedKFold from sklearn.model_selection import cross_val_score np.random.seed(0) np.set_printoptions(precision=6) y = [np.random.randint(3) for i in range(25)] X = (y + np.random.randn(25)).reshape(-1, 1) if Version(sklearn_version) < '0.18': cv5_idx = list(StratifiedKFold(y, n_folds=5, shuffle=False, random_state=0)) else: cv5_idx = list(StratifiedKFold(n_splits=5, shuffle=False, random_state=0).split(X, y)) cross_val_score(LogisticRegression(random_state=123), X, y, cv=cv5_idx)  Out[36]: array([ 0.6, 0.4, 0.6, 0.2, 0.6]) By executing the code above, we created a simple data set of random integers that shall represent our class labels. Next, we fed the indices of 5 cross-validation folds (cv3_idx) to the cross_val_score scorer, which returned 5 accuracy scores -- these are the 5 accuracy values for the 5 test folds. Next, let us use the GridSearchCV object and feed it the same 5 cross-validation sets (via the pre-generated cv3_idx indices): In [38]: if Version(sklearn_version) < '0.18': from sklearn.grid_search import GridSearchCV else: from sklearn.model_selection import GridSearchCV gs = GridSearchCV(LogisticRegression(), {}, cv=cv5_idx, verbose=3).fit(X, y)  Fitting 5 folds for each of 1 candidates, totalling 5 fits [CV] ................................................................ [CV] ....................................... , score=0.600000 - 0.0s [CV] ................................................................ [CV] ....................................... , score=0.400000 - 0.0s [CV] ................................................................ [CV] ....................................... , score=0.600000 - 0.0s [CV] ................................................................ [CV] ....................................... , score=0.200000 - 0.0s [CV] ................................................................ [CV] ....................................... , score=0.600000 - 0.0s  [Parallel(n_jobs=1)]: Done 1 out of 1 | elapsed: 0.0s remaining: 0.0s [Parallel(n_jobs=1)]: Done 2 out of 2 | elapsed: 0.0s remaining: 0.0s [Parallel(n_jobs=1)]: Done 5 out of 5 | elapsed: 0.0s finished  As we can see, the scores for the 5 folds are exactly the same as the ones from cross_val_score earlier. Now, the bestscore attribute of the GridSearchCV object, which becomes available after fitting, returns the average accuracy score of the best model: In [39]: gs.best_score_  Out[39]: 0.47999999999999998 As we can see, the result above is consistent with the average score computed the cross_val_score. In [40]: cross_val_score(LogisticRegression(), X, y, cv=cv5_idx).mean()  Out[40]: 0.47999999999999998 #### End comment.¶ # Working with bigger data - online algorithms and out-of-core learning¶ In [48]: import numpy as np import re from nltk.corpus import stopwords def tokenizer(text): text = re.sub('<[^>]*>', '', text) emoticons = re.findall('(?::|;|=)(?:-)?(?:$|\(|D|P)', text.lower())
text = re.sub('[\W]+', ' ', text.lower()) +\
' '.join(emoticons).replace('-', '')
tokenized = [w for w in text.split() if w not in stop]

def stream_docs(path):
with open(path, 'r', encoding='utf-8') as csv:
for line in csv:
text, label = line[:-3], int(line[-2])
yield text, label

In [49]:
next(stream_docs(path='./movie_data.csv'))

Out[49]:
('"In 1974, the teenager Martha Moxley (Maggie Grace) moves to the high-class area of Belle Haven, Greenwich, Connecticut. On the Mischief Night, eve of Halloween, she was murdered in the backyard of her house and her murder remained unsolved. Twenty-two years later, the writer Mark Fuhrman (Christopher Meloni), who is a former LA detective that has fallen in disgrace for perjury in O.J. Simpson trial and moved to Idaho, decides to investigate the case with his partner Stephen Weeks (Andrew Mitchell) with the purpose of writing a book. The locals squirm and do not welcome them, but with the support of the retired detective Steve Carroll (Robert Forster) that was in charge of the investigation in the 70\'s, they discover the criminal and a net of power and money to cover the murder.<br /><br />""Murder in Greenwich"" is a good TV movie, with the true story of a murder of a fifteen years old girl that was committed by a wealthy teenager whose mother was a Kennedy. The powerful and rich family used their influence to cover the murder for more than twenty years. However, a snoopy detective and convicted perjurer in disgrace was able to disclose how the hideous crime was committed. The screenplay shows the investigation of Mark and the last days of Martha in parallel, but there is a lack of the emotion in the dramatization. My vote is seven.<br /><br />Title (Brazil): Not Available"',
1)
In [50]:
def get_minibatch(doc_stream, size):
docs, y = [], []
try:
for _ in range(size):
text, label = next(doc_stream)
docs.append(text)
y.append(label)
except StopIteration:
return None, None
return docs, y

In [51]:
from sklearn.feature_extraction.text import HashingVectorizer
from sklearn.linear_model import SGDClassifier

vect = HashingVectorizer(decode_error='ignore',
n_features=2**21,
preprocessor=None,
tokenizer=tokenizer)

clf = SGDClassifier(loss='log', random_state=1, n_iter=1)
doc_stream = stream_docs(path='./movie_data.csv')

In [52]:
import pyprind
pbar = pyprind.ProgBar(45)

classes = np.array([0, 1])
for _ in range(45):
X_train, y_train = get_minibatch(doc_stream, size=1000)
if not X_train:
break
X_train = vect.transform(X_train)
clf.partial_fit(X_train, y_train, classes=classes)
pbar.update()

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In [53]:
X_test, y_test = get_minibatch(doc_stream, size=5000)
X_test = vect.transform(X_test)
print('Accuracy: %.3f' % clf.score(X_test, y_test))

Accuracy: 0.867

In [54]:
clf = clf.partial_fit(X_test, y_test)