The example shows how the combination of RDKit and PANDAS (http://pandas.pydata.org/) (and a bit SciKit-Learn (http://scikit-learn.org/stable/)) to do a simple data analysis. The Ames mutagenicity dataset compiled in Hansen et al., J. Chem. Inf. Model., 2009, 49 (9), pp 2077–2081 DOI: 10.1021/ci900161g was used as an example. The smiles_cas_N6512.smi input file can be obtained as supplement information from the article (http://pubs.acs.org/doi/suppl/10.1021/ci900161g).
import pandas as pd
from rdkit import Chem,rdBase
from rdkit.Chem import PandasTools
print 'PANDAS version ',pd.__version__
PANDAS version 0.10.0
Read the input file, which is tab-separated text, into a pandas dataframe. The input file has no column names, which is why these are provided as parameters.
data = pd.read_table(open('smiles_cas_N6512.smi','r'),header=None,names=['smiles','cas','mutagenic'])
The head() command shows the first 5 rows of a dataframe. It has an optional integer parameter that allows to specify how many rows are displayed. In most cases in this experiment this will be set two 2 rows to avoid using too much space.
data.head()
smiles | cas | mutagenic | |
---|---|---|---|
0 | O=C1c2ccccc2C(=O)c3c1ccc4c3[nH]c5c6C(=O)c7ccccc7C(=O)c6c8[nH]c9c%10C(=O)c%11ccccc%11C(=O)c%10ccc9c8c45 | 2475-33-4 | 0 |
1 | NNC(=O)CNC(=O)\C=N\#N | 820-75-7 | 1 |
2 | O=C1NC(=O)\C(=N/#N)\C=N1 | 2435-76-9 | 1 |
3 | NC(=O)CNC(=O)\C=N\#N | 817-99-2 | 1 |
4 | CCCCN(CC(O)C1=C\C(=N/#N)\C(=O)C=C1)N=O | 116539-70-9 | 1 |
The CAS numbers are well suited to serve as row keys.
data = data.set_index('cas')
data.head()
smiles | mutagenic | |
---|---|---|
cas | ||
2475-33-4 | O=C1c2ccccc2C(=O)c3c1ccc4c3[nH]c5c6C(=O)c7ccccc7C(=O)c6c8[nH]c9c%10C(=O)c%11ccccc%11C(=O)c%10ccc9c8c45 | 0 |
820-75-7 | NNC(=O)CNC(=O)\C=N\#N | 1 |
2435-76-9 | O=C1NC(=O)\C(=N/#N)\C=N1 | 1 |
817-99-2 | NC(=O)CNC(=O)\C=N\#N | 1 |
116539-70-9 | CCCCN(CC(O)C1=C\C(=N/#N)\C(=O)C=C1)N=O | 1 |
PANDAS has a describe command that shows the basic statistics of a dataframe. In the case, the information that can be obtained is only the number of rows (6512) and the roughly balanced mutagenicity class distribution.
data.describe()
mutagenic | |
---|---|
count | 6512.000000 |
mean | 0.537930 |
std | 0.498598 |
min | 0.000000 |
25% | 0.000000 |
50% | 1.000000 |
75% | 1.000000 |
max | 1.000000 |
The PandasTools module from rdkit offers functionality to add a molecule object type to the dataframe. In order to accelerate future substructure searches a substructure fingerprint can be precomputed during molecule construction. When the dataframe is displayed, the molecules are rendered as images using the RDKit's built-in drawing code.
PandasTools.AddMoleculeColumnToFrame(data,smilesCol='smiles',molCol='molecule',includeFingerprints=False)
data.head(2)
smiles | mutagenic | molecule | |
---|---|---|---|
cas | |||
2475-33-4 | O=C1c2ccccc2C(=O)c3c1ccc4c3[nH]c5c6C(=O)c7ccccc7C(=O)c6c8[nH]c9c%10C(=O)c%11ccccc%11C(=O)c%10ccc9c8c45 | 0 | |
820-75-7 | NNC(=O)CNC(=O)\C=N\#N | 1 | None |
Some problematic smiles strings (e.g. compound 820-75-7) lead to empty molecules. The respective rows can be filtered using the "notnull" mask.
data = data.ix[data['molecule'].notnull()]
data.describe()
mutagenic | |
---|---|
count | 6450.000000 |
mean | 0.533798 |
std | 0.498895 |
min | 0.000000 |
25% | 0.000000 |
50% | 1.000000 |
75% | 1.000000 |
max | 1.000000 |
data.head(2)
smiles | mutagenic | molecule | |
---|---|---|---|
cas | |||
2475-33-4 | O=C1c2ccccc2C(=O)c3c1ccc4c3[nH]c5c6C(=O)c7ccccc7C(=O)c6c8[nH]c9c%10C(=O)c%11ccccc%11C(=O)c%10ccc9c8c45 | 0 | |
105149-00-6 | CC(=O)OC1(CCC2C3C=C(Cl)C4=CC(=O)OCC4(C)C3CCC12C)C(=O)C | 0 |
Pandas offers a grouping functionality that allows for more detailed statistics.
data.groupby('mutagenic').describe().unstack()
mutagenic | ||||||||
---|---|---|---|---|---|---|---|---|
count | mean | std | min | 25% | 50% | 75% | max | |
mutagenic | ||||||||
0 | 3007 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |
1 | 3443 | 1 | 0 | 1 | 1 | 1 | 1 | 1 |
The "ix" row selection, the groupby and other PANDAS methods are able to handle boolean mask arrays similarily to what numpy does. This capability can be extended to substructure filters using the RDKit PandasTools integration.
#define a structure pattern
from rdkit.Chem.Draw import IPythonConsole
nitroso = Chem.MolFromSmiles('N=O')
nitroso
Importing the RDKit PandasTools module has the side-effects of adding HTML rendering of molecules (discussed above) and adding a ge (>=) operator that triggers a substructure search, i.e. molX >= molY returns the same boolean result as checking if the substructure molY is contained in molX.
Thus, the next two examples show the mutagencity class distribution for molecules depending on wether they contain a nitroso or a naphthalene motif.
data.groupby(data['molecule'] >= nitroso).describe().unstack()
mutagenic | ||||||||
---|---|---|---|---|---|---|---|---|
count | mean | std | min | 25% | 50% | 75% | max | |
molecule | ||||||||
False | 5217 | 0.461760 | 0.498583 | 0 | 0 | 0 | 1 | 1 |
True | 1233 | 0.838605 | 0.368044 | 0 | 1 | 1 | 1 | 1 |
polyarom = Chem.MolFromSmiles('c1cccc2c1cccc2')
polyarom
data.groupby(data['molecule'] >= polyarom).describe().unstack()
mutagenic | ||||||||
---|---|---|---|---|---|---|---|---|
count | mean | std | min | 25% | 50% | 75% | max | |
molecule | ||||||||
False | 5533 | 0.488162 | 0.499905 | 0 | 0 | 0 | 1 | 1 |
True | 917 | 0.809160 | 0.393177 | 0 | 1 | 1 | 1 | 1 |
Thus, 917 compounds contains the naphtalene substructure and about 81% of those 917 are classified as mutagenic.
RDKit has several molecular fingerprint implementations that could be used as a molecule representation for building a mutagenicity model. These can be used most effectively with the scikit-learn machine-learning methods by converting the fingerprints to numpy arrays first. Performing a row-wise custom computation can be most easily realized in Pandas using the combination of a lambda function and the dataframe.apply method. Unfortunately, this pattern does not work directly for functions returning an array, which is why the fingerprints have to be wrapped in a dummy container class FP.
from rdkit.Chem import AllChem
from rdkit import DataStructs
class FP:
def __init__(self, fp):
self.fp = fp
def __str__(self):
return self.fp.__str__()
def computeFP(x):
#compute depth-2 morgan fingerprint hashed to 1024 bits
fp = AllChem.GetMorganFingerprintAsBitVect(x,2,nBits=1024)
res = numpy.zeros(len(fp),numpy.int32)
#convert the fingerprint to a numpy array and wrap it into the dummy container
DataStructs.ConvertToNumpyArray(fp,res)
return FP(res)
data['FP'] = data.apply(lambda row: computeFP(row['molecule']), axis=1)
#filter potentially failed fingerprint computations
data = data.ix[data['FP'].notnull()]
The "ix" row filter works for row indices as well as boolean masks. We use this here to randomly split the data into training and test sets
import random
rand = random.Random()
rand.seed(42)
train = rand.sample(data.index, len(data)/2)
trainData = data.ix[train]
testData = data.drop(train)
from sklearn.ensemble import RandomForestClassifier
model = RandomForestClassifier(random_state = 42)
#resolve wrapped fingerprints
X = [x.fp for x in trainData['FP']]
y = trainData['mutagenic']
model.fit(X,y)
#resolve wrapped fingerprints and apply the model on the test data
prediction = model.predict([x.fp for x in testData['FP']])
A simple numerical report can be obtained from scikit-learn easily using dataframe columns
from sklearn.metrics import metrics
print metrics.confusion_matrix(testData['mutagenic'],prediction)
print metrics.classification_report(testData['mutagenic'],prediction)
[[1107 417] [ 372 1329]] precision recall f1-score support 0 0.75 0.73 0.74 1524 1 0.76 0.78 0.77 1701 avg / total 0.76 0.76 0.76 3225
For a more detailed analysis, probabilistic predictions can be obtained from the scikit-learn RandomForest model and inserted directly into the dataframe
testData['prediction'] = model.predict([x.fp for x in testData['FP']])
testData['probability'] = [p[1] for p in model.predict_proba([x.fp for x in testData['FP']])]
testData.head(2)
smiles | mutagenic | molecule | FP | prediction | probability | |
---|---|---|---|---|---|---|
2475-33-4 | O=C1c2ccccc2C(=O)c3c1ccc4c3[nH]c5c6C(=O)c7ccccc7C(=O)c6c8[nH]c9c%10C(=O)c%11ccccc%11C(=O)c%10ccc9c8c45 | 0 | [0 0 0 ..., 0 0 0] | 1 | 0.525000 | |
105149-00-6 | CC(=O)OC1(CCC2C3C=C(Cl)C4=CC(=O)OCC4(C)C3CCC12C)C(=O)C | 0 | [0 0 0 ..., 0 0 0] | 0 | 0.208333 |
testData.sort(columns='probability').head(2)
smiles | mutagenic | molecule | FP | prediction | probability | |
---|---|---|---|---|---|---|
109-43-3 | CCCCOC(=O)CCCCCCCCC(=O)OCCCC | 0 | [0 0 0 ..., 0 0 0] | 0 | 0 | |
111-87-5 | CCCCCCCCO | 0 | [0 0 0 ..., 0 0 0] | 0 | 0 |
testData.sort(columns='probability',ascending=False).head(2)
smiles | mutagenic | molecule | FP | prediction | probability | |
---|---|---|---|---|---|---|
5296-38-8 | C(Oc1ccc(Cc2ccccc2)cc1)C3CO3 | 1 | [0 0 0 ..., 0 0 0] | 1 | 1 | |
17024-19-0 | [O-][N+](=O)c1ccc2ccc3ccccc3c2c1 | 1 | [0 0 0 ..., 0 0 0] | 1 | 1 |
Pandas offers a range of data visualization tools that can be easily used to generate reports for a performance analysis of a machine learning models. The next example shows how to create a plot that shows the binary true mutagenicity class distribution on the test set for the discretized range of predicted mutagenic probabilities.
#assign the predicted probabilities to discrete bins
testData['binnedProb'] = pd.cut(testData['probability'],bins=[-0.1,0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9,1.1],labels=False)
temp = testData.groupby(['binnedProb','mutagenic'])['mutagenic'].size().unstack()
print temp
temp.plot(kind='bar',stacked=True,)
mutagenic 0 1 binnedProb 0 289 26 1 203 53 2 240 66 3 194 107 4 181 120 5 151 144 6 107 209 7 55 244 8 63 335 9 41 397
<matplotlib.axes.AxesSubplot at 0x10c8795d0>
The same approach can also be used to plot the frequency of compounds containing a specific substrstructure (naphtalene in this case) with respect to the predicted probability of being mutagenic. This indicates that the model possibly has learned to recognize this motif (i.e the fingerprint bits corresponding to it) as an indicator of mutagenicity.
polyarom = Chem.MolFromSmiles('c1cccc2c1cccc2')
polyarom
testData.groupby(['binnedProb',testData['molecule'] >= polyarom])['mutagenic'].size().unstack().plot(kind='bar',stacked=True,)
<matplotlib.axes.AxesSubplot at 0x10a292050>
This observation is supported by comparing the probability distributions dependent on the presence of the substructure. The predicted probability of being mutagenic is nearly twice if the substructure is present in a molecule.
temp = testData.copy()
temp['containsMotif'] = temp['molecule'] >= polyarom
temp.boxplot('probability',by='containsMotif')
<matplotlib.axes.AxesSubplot at 0x10e205990>
The allows to conduct RDKit fingerprint operations like computing a Tanimoto similarity matrix quite directly on the dataframe.
#del trainData['explFP']
def addExplFP(df,molColumn):
fpCache = []
for mol in df[molColumn]:
res = AllChem.GetMorganFingerprintAsBitVect(mol,2,nBits=1024)
fpCache.append(res)
arr = np.empty((len(df),), dtype=np.object)
arr[:]=fpCache
S = pd.Series(arr,index=df.index,name='explFP')
return df.join(pd.DataFrame(S))
trainData = addExplFP(trainData,'molecule')
trainData.head(2)
smiles | mutagenic | molecule | FP | explFP | |
---|---|---|---|---|---|
1640-39-7 | CC1=Nc2ccccc2C1(C)C | 0 | [0 0 0 ..., 0 0 0] | [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] | |
100-39-0 | BrCc1ccccc1 | 1 | [0 0 0 ..., 0 0 0] | [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] |
from rdkit import DataStructs
fpList = trainData['explFP'].tolist()
dm=[]
for i,fp in enumerate(fpList):
dm.extend(DataStructs.BulkTanimotoSimilarity(fp,fpList[1+i:],returnDistance=True))
dm = array(dm)
It is also possible to store the fingerprints as numpy arrays, which allows for direct application in scikit-learn.
def convertToNumpy(df,fpCol):
fpCache = []
for fp in df[fpCol]:
res = numpy.zeros(len(fp),numpy.int32)
DataStructs.ConvertToNumpyArray(fp,res)
fpCache.append(res)
'''
it is necessary to constructs an empty object array in advance and fill that later,
because directly initializing an array with the fingerprint would trigger the numpy
type recognition and result in a array of integers that again would trigger pandas
to construct a Series object per bit position
'''
arr = np.empty((len(df),), dtype=np.object)
arr[:]=fpCache
S = pd.Series(arr,index=df.index,name='npFP')
return df.join(pd.DataFrame(S))
trainData = convertToNumpy(trainData,'explFP')
trainData.head()
smiles | mutagenic | molecule | FP | explFP | npFP | |
---|---|---|---|---|---|---|
1640-39-7 | CC1=Nc2ccccc2C1(C)C | 0 | [0 0 0 ..., 0 0 0] | [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 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100-39-0 | BrCc1ccccc1 | 1 | [0 0 0 ..., 0 0 0] | [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 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79-94-7 | CC(C)(c1cc(Br)c(O)c(Br)c1)c2cc(Br)c(O)c(Br)c2 | 0 | [0 0 0 ..., 0 0 0] | [0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 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1822-51-1 | ClCc1ccncc1 | 0 | [0 0 0 ..., 0 0 0] | [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 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594-71-8 | CC(C)(Cl)[N+](=O)[O-] | 1 | [0 0 0 ..., 0 0 0] | [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 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This avoids having to use wrapper classes and additional list comprehensions to prepare the data for scikit-learn.
model = RandomForestClassifier()
#resolve wrapped fingerprints
#X = [x.fp for x in trainData['FP']]
#y = trainData['mutagenic']
model.fit(np.vstack(trainData['npFP']),trainData['mutagenic'])
RandomForestClassifier(bootstrap=True, compute_importances=False, criterion='gini', max_depth=None, max_features='auto', min_density=0.1, min_samples_leaf=1, min_samples_split=1, n_estimators=10, n_jobs=1, oob_score=False, random_state=<mtrand.RandomState object at 0x1063b4300>, verbose=0)
Pandas makes it very simple to compute statistics for data categories. The only things required is a discrete dataframe column that allows the data being grouped with respect to the unique values occuring in that column. This concept can be also used for computing property distribution with respect to molecular structures if the molecules are classified into categories. One way to obtain the latter would be to conduct a simple structural clustering using the molecular fingerprints.
from rdkit import DataStructs
from rdkit.ML.Cluster import Butina
def ClusterFps(fps,cutoff=0.2):
# first generate the distance matrix:
dists = []
nfps = len(fps)
for i in range(1,nfps):
sims = DataStructs.BulkTanimotoSimilarity(fps[i],fps[:i])
dists.extend([1-x for x in sims])
# now cluster the data:
cs = Butina.ClusterData(dists,nfps,cutoff,isDistData=True)
return cs
#the explicit bitvector column constructured a few steps earlier, can not directly used to perform a Butina clustering using the RDKit implementation
bt_clusters = ClusterFps(trainData['explFP'].tolist(),cutoff=0.3)
"bt_clusters" is a tuple of tuples aggregation the compound indices that belong to the same cluster together. In order the cluster information to the dataframe, this representation has to be converted into either a list or a numpy array. After the next step the dataframe contains an additional column containing the index of the centroid for the cluster the respective row to assigned to.
cluster_map = np.empty(len(trainData))
cluster_map[:]=-1
for _c in bt_clusters:
if len(_c)<5: continue
centroid = _c[0]
for it in _c:
cluster_map[it]=centroid
trainData['btCluster'] = cluster_map
Using the centroid index it is simple to add the corresponding molecule object to the dataframe rows. This result in dataframe that associates each molecule with its centroid structure.
def getMoleculeForCluster(c):
return trainData.ix[trainData.index[int(c)]]['molecule']
cData = trainData.ix[trainData['btCluster'] != -1]
cData['Centroid'] = cData.apply(lambda row: getMoleculeForCluster(row['btCluster']),axis=1)
cData['Centroid CAS'] = cData.apply(lambda row: str(trainData.index[int(row['btCluster'])]),axis=1)
cData[['molecule','Centroid','btCluster','Centroid CAS']].tail(2)
molecule | Centroid | btCluster | Centroid CAS | |
---|---|---|---|---|
954-46-1 | 1802 | 159092-71-4 | ||
51938-12-6 | 2888 | 51938-13-7 |
#add an example numeric column to compute statistics for
cData['nAtoms'] = cData.apply(lambda row: row['molecule'].GetNumAtoms(),axis=1)
Finally, the cluster-wise statistic can be easily obtained by using the centroid index column as grouping key. Additionally, it is possible by using multiple keys and choosing the right ordering to show the statistics directly associated with the centroid structure.
from IPython.display import HTML,display
temp = dict([(row[1]['btCluster'],row[1]['Centroid']) for row in cData.iterrows()])
tC = cData.set_index('Centroid',False)
#groupby clusterID (string doesn't work well) and compute statistic
tC = tC.groupby('btCluster')
tempC = tC.describe()[['mutagenic','nAtoms']]
#display(HTML(tempC.to_html()))
#the MCS was dropped because describe doesn't work on non-numerics, thus it has to be mapped back
#every substatistic is now associated with an instance of the MCS
def mapMCS(row):
return temp[row.name[0]]
tempC['Centroid'] = tempC.apply(lambda row: mapMCS(row),axis=1)
#display(HTML(tempC.to_html()))
#create a second index level using the MCS and reorder the indices
index = tempC.index
tempC = tempC.set_index('Centroid', append=True)
#display(HTML(tempC.to_html()))
tempC = tempC.reorder_levels([0,'Centroid',1])
display(HTML(tempC.ix[1802].to_html()))
mutagenic | nAtoms | ||
---|---|---|---|
Centroid | |||
count | 5 | 5.000000 | |
mean | 1 | 20.600000 | |
std | 0 | 2.880972 | |
min | 1 | 17.000000 | |
25% | 1 | 20.000000 | |
50% | 1 | 20.000000 | |
75% | 1 | 21.000000 | |
max | 1 | 25.000000 |