This notebook was prepared by Donne Martin. Source and license info is on GitHub.
o = valid cell x = invalid cell 0 1 2 3 0 o o o o 1 o x o o 2 o o x o 3 x o o o 4 o o x o 5 o o o x 6 o x o x 7 o x o o
expected = [(0, 0), (1, 0), (2, 0),
(2, 1), (3, 1), (4, 1),
(5, 1), (5, 2), (6, 2),
(7, 2), (7, 3)]
Refer to the Solution Notebook. If you are stuck and need a hint, the solution notebook's algorithm discussion might be a good place to start.
class Grid(object):
def find_path(self, matrix):
# TODO: Implement me
pass
The following unit test is expected to fail until you solve the challenge.
# %load test_grid_path.py
import unittest
class TestGridPath(unittest.TestCase):
def test_grid_path(self):
grid = Grid()
self.assertEqual(grid.find_path(None), None)
self.assertEqual(grid.find_path([[]]), None)
max_rows = 8
max_cols = 4
matrix = [[1] * max_cols for _ in range(max_rows)]
matrix[1][1] = 0
matrix[2][2] = 0
matrix[3][0] = 0
matrix[4][2] = 0
matrix[5][3] = 0
matrix[6][1] = 0
matrix[6][3] = 0
matrix[7][1] = 0
result = grid.find_path(matrix)
expected = [(0, 0), (1, 0), (2, 0),
(2, 1), (3, 1), (4, 1),
(5, 1), (5, 2), (6, 2),
(7, 2), (7, 3)]
self.assertEqual(result, expected)
matrix[7][2] = 0
result = grid.find_path(matrix)
self.assertEqual(result, None)
print('Success: test_grid_path')
def main():
test = TestGridPath()
test.test_grid_path()
if __name__ == '__main__':
main()
Review the Solution Notebook for a discussion on algorithms and code solutions.