The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385 The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025 Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

In [2]:

def squares(num):
    for x in range(1, num, 1):
        yield x ** 2

In [10]:

sum([i for i in squares(11)])

Out[10]:

In [7]:

def total(num):
    for x in range(1, num, 1):
        yield x

In [12]:

sum([i for i in total(11)]) ** 2

Out[12]:

In [15]:

def square_difference(num):
    x = sum([i for i in squares(num)])
    y = sum([i for i in total(num)]) ** 2
    
    print y - x

In [17]:

square_difference(101)

25164150

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