#!/usr/bin/env python
# coding: utf-8

# #Advanced Functions Test 
# 
# ### For this test, you should use the built-in functions to be able to write the requested functions in one line.

# ###Problem 1
# 
# Use map to create a function which finds the length of each word in the phrase
# (broken by spaces) and return the values in a list.
# 
# The function will have an input of a string, and output a list of integers.

# In[1]:


def word_lengths(phrase):
    
    pass


# In[4]:


word_lengths('How long are the words in this phrase')


# ###Problem 2 
# 
# Use reduce to take a list of digits and return the number that they
# correspond to. *Do not convert the integers to strings!* 

# In[2]:


def digits_to_num(digits):
    
    pass


# In[8]:


digits_to_num([3,4,3,2,1])


# ###Problem 3
# 
# Use filter to return the words from a list of words which start with a target letter.

# In[3]:


def filter_words(word_list, letter):
    
    pass


# In[10]:


l = ['hello','are','cat','dog','ham','hi','go','to','heart']
filter_words(l,'h')


# ###Problem 4
# 
# Use zip and list comprehension to return a list of the same length where each value is the two strings from
# L1 and L2 concatenated together with connector between them. Look at the example output below:

# In[4]:


def concatenate(L1, L2, connector):
    
    pass


# In[14]:


concatenate(['A','B'],['a','b'],'-')


# ###Problem 5
# 
# Use enumerate and other skills to return a dictionary which has the values of the list as keys and the index as the value. You may assume that a value will only appear once in the given list.
# 

# In[5]:


def d_list(L):
    
    pass


# In[20]:


d_list(['a','b','c'])


# ###Problem 6
# 
# Use enumerate and other skills from above to return the count of the number of items in the list whose value equals its index.
# 

# In[6]:


def count_match_index(L):
   
    pass


# In[24]:


count_match_index([0,2,2,1,5,5,6,10])


# # Great Job!