# 01 딕셔너리(Dictionaries)에 대한 반복자(Iterators)
my_dict = {
"name" : "xuruiqi",
"gender" : "male",
"birthday" : "19910527"
}
print (my_dict.items())
dict_items([('name', 'xuruiqi'), ('gender', 'male'), ('birthday', '19910527')])
# 02 keys()와 values()
my_dict = {
"name" : "xuruiqi",
"gender" : "male",
"birthday" : "19910527"
}
print (my_dict.keys())
print (my_dict.values())
dict_keys(['name', 'gender', 'birthday']) dict_values(['xuruiqi', 'male', '19910527'])
# 03 'in' 연산자
my_dict = {
"name" : "xuruiqi",
"gender" : "male",
"birthday" : "19910527"
}
for e in my_dict:
print (e, my_dict[e])
# 딕셔너리는 순서가 보장되지 않습니다!
name xuruiqi gender male birthday 19910527
# 04 리스트 만들기
evens_to_50 = [i for i in range(51) if i % 2 == 0]
print (evens_to_50)
[0, 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50]
# 05 리스트 내포(List Comprehensions) 문법
even_squares = [x ** 2 for x in range(1, 11) if x % 2 == 0]
even_squares
[4, 16, 36, 64, 100]
# 06 여러분의 차례입니다!
cubes_by_four = [x ** 3 for x in range(1, 11) if (x ** 3 % 4 == 0)]
print (cubes_by_four)
[8, 64, 216, 512, 1000]
# 07 리스트 슬라이싱(List Slicing) 문법
l = [i ** 2 for i in range(1, 11)]
# Should be [1, 4, 9, 16, 25, 36, 49, 64, 81, 100]
print (l[2:9:2])
[9, 25, 49, 81]
# 08 색인(index) 생략하기
my_list = range(1, 11) # List of numbers 1 - 10
# Add your code below!
print (my_list[: : 2])
# 리스트의 내용을 출력하려면 (Python3)
print (*my_list[: : 2])
range(1, 11, 2) 1 3 5 7 9
# 09 리스트 뒤집기
my_list = range(1, 11)
# Add your code below!
backwards = my_list[ : : -1]
print(*backwards)
10 9 8 7 6 5 4 3 2 1
# 10 스트라이드 길이 (Stride Length)
to_one_hundred = range(101)
# Add your code below!
backwards_by_tens = to_one_hundred[ : : -10]
print (*backwards_by_tens)
100 90 80 70 60 50 40 30 20 10 0
# 11 연습이 최고를 만듭니다 Practice Makes Perfect
to_21 = range(1, 22)
odds = to_21[ : : 2] #[x for x in to_21 if x % 2 != 0]
middle_third = range(int(21 / 3 + 1), int(21 / 3 * 2 + 1))
print(*middle_third)
# 3등분의 중간
8 9 10 11 12 13 14
# 12 익명 함수 Anonymous Functions
my_list = range(16)
print (*filter(lambda x: x % 3 == 0, my_list))
0 3 6 9 12 15
# 13 람다(Lambda) 문법
languages = ["HTML", "JavaScript", "Python", "Ruby"]
print (*filter(lambda x: x == "Python", languages))
Python
# 14 해보세요!
squares = [x ** 2 for x in range(1, 11)]
print (*filter(lambda x: x >= 30 and x <= 70, squares))
36 49 64
# 15 딕셔너리(Dictionaries) 반복하기
movies = {
"Monty Python and the Holy Grail": "Great",
"Monty Python's Life of Brian": "Good",
"Monty Python's Meaning of Life": "Okay"
}
print (movies.items())
dict_items([("Monty Python's Life of Brian", 'Good'), ('Monty Python and the Holy Grail', 'Great'), ("Monty Python's Meaning of Life", 'Okay')])
# 16 리스트 내포(list comprehension) 이해하기
threes_and_fives = [x for x in range(1, 16) if x % 3 == 0 or x % 5 == 0]
threes_and_fives
[3, 5, 6, 9, 10, 12, 15]
# 17 리스트 슬라이싱(List Slicing)
garbled = "!XeXgXaXsXsXeXmX XtXeXrXcXeXsX XeXhXtX XmXaX XI"
message = "".join(x for x in garbled[ : : -1] if x != 'X')
print (message)
I am the secret message!
# 18 람다 표현
garbled = "IXXX aXXmX aXXXnXoXXXXXtXhXeXXXXrX sXXXXeXcXXXrXeXt mXXeXsXXXsXaXXXXXXgXeX!XX"
message = filter(lambda x: x != 'X', garbled)
print (*message)
I a m a n o t h e r s e c r e t m e s s a g e !